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0.64x-0.00012x^2=0
a = -0.00012; b = 0.64; c = 0;
Δ = b2-4ac
Δ = 0.642-4·(-0.00012)·0
Δ = 0.4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.64)-\sqrt{0.4096}}{2*-0.00012}=\frac{-0.64-\sqrt{0.4096}}{-0.00024} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.64)+\sqrt{0.4096}}{2*-0.00012}=\frac{-0.64+\sqrt{0.4096}}{-0.00024} $
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